33. (a) If L is the distance between the lenses, then according to Fig. 35-17, the tube length is s =
L - fob - fey =25.0cm- 4.00 cm - 8.00 cm= 13.0cm.
(b) We solve (1/p) +(1/i) =(1/fob) for p. The image distance is i = fob + s =4.00 cm+ 13.0cm=
17.0cm, so
ifob (17.0 cm)(4.00 cm)
p = = =5.23 cm .
i - fob 17.0cm- 4.00 cm
(c) The magnification of the objective is
i 17.0cm
m = - = - = -3.25 .
p 5.23 cm
(d) The angular magnification of the eyepiece is
25 cm 25 cm
m¸ = = =3.13 .
fey 8.00 cm
(e) The overall magnification of the microscope is
M = mm¸ =(-3.25)(3.13) = -10.2 .
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