43. (a) (b) and (c) Since m =+0.250, we have i = -0.25p which indicates that the image is virtual (as well as being diminished in size). We conclude from this that the mirror is convex and that f < 0; in fact, f = -2.00 cm. Substituting i = -p/4 into Eq. 35-4 produces 1 4 3 1 - = - = p p p f Therefore, we find p =6.00 cm and i = -1.50 cm.