30a section 5 solutions


Mehran Sahami Handout #30A
CS 106A November 1, 2007
Solution to Section #5
Portions of this handout by Eric Roberts
1. Word count
/*
* File: WordCount.java
* --------------------
* Counts the characters, words, and lines in a file.
*/
import acm.program.*;
import java.io.*;
public class WordCount extends ConsoleProgram {
public void run() {
int lines = 0;
int words = 0;
int chars = 0;
BufferedReader rd = openFileReader("File: ");
try {
while (true) {
String line = rd.readLine();
if (line == null) break;
lines++;
words += countWords(line);
chars += line.length();
}
rd.close();
} catch (IOException ex) {
println("An I/O exception has occurred");
}
println("Lines = " + lines);
println("Words = " + words);
println("Chars = " + chars);
}
/**
* Asks the user for the name of an input file and returns a
* BufferedReader attached to its contents. If the file does
* not exist, the user is given another chance to try.
*/
private BufferedReader openFileReader(String prompt) {
BufferedReader rd = null;
while (rd == null) {
String name = readLine(prompt);
try {
rd = new BufferedReader(new FileReader(name));
} catch (IOException ex) {
println("Can't open that file.");
}
}
return rd;
}
 2 
/**
* Counts the words (consecutive strings of letters and/or digits)
* in the input line.
*/
private int countWords(String line) {
boolean inWord = false;
int words = 0;
for (int i = 0; i < line.length(); i++) {
char ch = line.charAt(i);
if (Character.isLetterOrDigit(ch)) {
inWord = true;
} else {
if (inWord) words++;
inWord = false;
}
}
if (inWord) words++;
return words;
}
}
2. Histogram
/*
* File: Histogram.java
* --------------------
* This program reads a list of exam scores, with one score per line.
* It then displays a histogram of those scores, divided into the
* ranges 0 9, 10 19, 20 29, and so forth, up to the range containing
* only the value 100.
*/
import acm.program.*;
import acm.util.*;
import java.io.*;
public class Histogram extends ConsoleProgram {
public void run() {
initHistogram();
readScoresIntoHistogram();
printHistogram();
}
/* Initializes the histogram array */
private void initHistogram() {
histogramArray = new int[11];
for (int i = 0; i <= 10; i++) {
histogramArray[i] = 0;
}
}
 3 
/* Reads the exam scores, updating the histogram */
private void readScoresIntoHistogram() {
try {
BufferedReader rd
= new BufferedReader(new FileReader(DATA_FILE));
while (true) {
String line = rd.readLine();
if (line == null) break;
int score = Integer.parseInt(line);
if (score < 0 || score > 100) {
throw new ErrorException("That score is out of range");
} else {
int range = score / 10;
histogramArray[range]++;
}
}
} catch (IOException ex) {
throw new ErrorException(ex);
}
}
/* Displays the histogram */
private void printHistogram() {
for (int range = 0; range <= 10; range++) {
String label;
switch (range) {
case 0: label = "00-09"; break;
case 10: label = " 100"; break;
default:
label = (10 * range) + "-" + (10 * range + 9);
break;
}
String stars = createStars(histogramArray[range]);
println(label + ": " + stars);
}
}
/* Creates a string consisting of n stars */
private String createStars(int n) {
String stars = "";
for (int i = 0; i < n; i++) {
stars += "*";
}
return stars;
}
/* Private instance variables */
private int[] histogramArray;
/* Name of the data file */
private static final String DATA_FILE = "MidtermScores.txt";
}
 4 
3. Unique Names
/*
* File: UniqueNames.java
* ----------------------
* This program asks the user for a list of names (one per line)
* until the user enters a blank line. Then the program prints
* out the list of names entered, where each name is listed only
* once (i.e., uniquely) no matter how many times the user entered
* the name in the program.
*/
import acm.program.*;
import java.util.*;
public class UniqueNames extends ConsoleProgram {
public void run() {
ArrayList list = new ArrayList();
while (true) {
String name = readLine("Enter name: ");
if (name.equals("")) break;
if (!list.contains(name)) {
list.add(name);
}
}
println("Unique name list contains:");
printList(list);
}
/* Prints out contents of ArrayList, one element per line */
private void printList(ArrayList list) {
for(int i = 0; i < list.size(); i++) {
println(list.get(i));
}
}
}


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