2949775112

2949775112



Solving the integral in I(x) by parts and substituting the resulting expression in (3.15), we get

E[Xl(r,n,m,k)X3 (s,n,m,k)\ — E[Xl{r,n,m,k)X3 (s — l,n,m,k)\

- -r.tr - ms1- r -1)1 r r

x[hm(F(y)) - hm(F(x))]—'-1[F(y)]'" d,ydx

the constant of integration vanishes sińce the integral in I(x) is a definite integral. On using the relation (1.3), we obtain

E[Xl(r, n, m, k)X3(s, n, m, k)] — E[Xl(r, n,m, k)X3 (s 1 ,n,m, fc)] jaCs.

a/57s(r — l)!(s o/?7s(r — l)!(s — r — 1)!

«Wf(r))-L(W

and hence the result given in (3.14).

Remark 3.2 Setting m = 0, fc = 1 in (3.14), we obtain recurrence relations for product moments of order statistics of the type II exponentiated log-logistic distribution in the form

1 - afln-. +!))*!*•”1 =    + af,<Ż-s+l)ElX^]-

Remark 3.3 Putting m = — 1, k > 1 in (3.5), we get the recurrence relations for product moments of upper k records of the type II exponentiated log-logistic distribution in the form

Ratio moments of gos from type II exponentiated log-logistic distribution can be obtain by the following Theorem.

3.5. Theorem. For type II ezponentiated log-logistic distribution as giuen in (1.2)

E[X*(r,n,m,k)Xj ^(s,n,m,k)] =    -r—— -r-^-

UU pi9!r(i-p)r(i + i-p)

(3.16)


(3.17)


xn:,(i+^)n;,łl(i+“)' fi>3'

Proof From (1.6), we have

E[Xl(r,n,m,k)X3 p (s,n,m,fc)] =


Cs-1

(r — l)!(s — r — l)!(m + l)8-2

X f°° xi[F(x)](’-r+*-°Xm+1)-1f(x)J(x)dx, Jo



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