scan00012

scan00012



among groups within groups

Step 3 -/ANOVA table


So^rce of vaĄation

r

55

MS

Fs

Expected

MS

i

a-l

^^among

ss„

a-l

MS.^

a‘ + n„o;

Y-Y '

SSw|th,n

ss.^

o2

Y-Y ^

SStoui

total


among groups within groups

Step 3 -/ANOVA table


Ąurceof Ąr/atńn j

dr

SS

MS

Fs

Y-f /

3

1807.73

602.58

5.26

Y-Y '

33

3778.00

114.48

Y-Y

36

5585.73

total


| Step 4 - Conclusion

i Step 5 - Estimation of variance 1 components (model II)

JP

3p

Since sample size differs among groups, no single

■ The corresponding p-value for calculated F statistic

value of n is appropriate. We therefore use an

with [dfsmong/ dfw(thin] degrees of freedom is equal to

„average" n - this is not the arithmetic mean of the

0.0045 < 0.05.

n.'s, but is

l

n„ *-r-

[t.-ŁSl.

■ We reject the H0 hypothesis at p < 0.005.

# a-l

i-t V‘ n,

V. i-*-1 1 y

■ There is a significant added variance component

1 [[8 + 10 + 13+6] 8

+ 10ł + 132 +62)

among hosts for width of scutum in larval ticks

4-1 1

8 + 10 + 13 + 6 J

9.009


i Step 5 - Estimation of variance

i Step 5 - Estimation of variance

components (model II)

1 components (model II)

We may estimate the variance component as follows

Percent of variation among groups

, MS_-MS^ 602.58-114.48

ww. 54.179

A n„ 9.009 because

- - x 100 =-x 100 = 32.1%

s2+*i 114.48 + 54.179

e(ms*m)- «' +“.<*! E(MS.«u.)=0J

so

Ms

MSw-kto=,2

The coefficient of interclass correlation rj=0.321


2


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